When cyclist squeezes her brake lever, she can stop with an acceleration of - 3.0 m/s^2 how far will her bike travel while coming to a complete stop if her initial speed was 11 m/s

We shall use the formula

v² = u² + 2as

where

v = final speed. v = 0 because the cyclist comes to a complete stop.

u = initial speed. u = 11 m/s, given

a = acceleration. a = - 3.0 m/s², given

s = distance traveled, m.

Therefore

0 = 11² + 2 (-3.0) * s

0 = 121 - 6s

That is,

6s = 121

s = 121/6 = 20.167 m

Answer: 20.2 m (nearest tenth)