The length of a rectangle is 5cm greater than its width. The perimeter is 58. What are the dimensions of the rectangle

Perimeter = 2w+2l

l=w+5

Substitute for l

p = 2w+2 (w+5)

p = 2w+2w+10

p = 4w+10

58=4w+10

48=4w

12 = w

Plug in the width to find length.

l = 12+5

l=17

Final answer: Length-17 cm, Width-12 cm

Write two equations:

l + w = 58

l + 5 = w

substitute and solve

l + l + 5 = 58

2l = 53

l=26.5

w=31.5

26.5cm x 31.5cm