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14 January, 02:34

What is the factored form of 8x^24-27y^6

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  1. 14 January, 02:45
    0
    8x24-27y6 Final result : (2x8 - 3y2) • (4x16 + 6x8y2 + 9y4)

    Step by step solution : Step 1 : Skip Ad

    Equation at the end of step 1 : (8 • (x24)) - 33y6 Step 2 : Equation at the end of step 2 : 23x24 - 33y6 Step 3 : Trying to factor as a Difference of Squares:

    3.1 Factoring: 8x24-27y6

    Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

    Proof : (A+B) • (A-B) =

    A2 - AB + BA - B2 =

    A2 - AB + AB - B2 =

    A2 - B2

    Note : AB = BA is the commutative property of multiplication.

    Note : - AB + AB equals zero and is therefore eliminated from the expression.

    Check : 8 is not a square!

    Ruling : Binomial can not be factored as the

    difference of two perfect squares

    Trying to factor as a Difference of Cubes:

    3.2 Factoring: 8x24-27y6

    Theory : A difference of two perfect cubes, a3 - b3 can be factored into

    (a-b) • (a2 + ab + b2)

    Proof : (a-b) • (a2+ab+b2) =

    a3 + a2b + ab2 - ba2 - b2a - b3 =

    a3 + (a2b - ba2) + (ab2 - b2a) - b3 =

    a3 + 0+0 + b3 =

    a3 + b3

    Check : 8 is the cube of 2

    Check : 27 is the cube of 3

    Check : x24 is the cube of x8

    Check : y6 is the cube of y2

    Factorization is:

    (2x8 - 3y2) • (4x16 + 6x8y2 + 9y4)

    Trying to factor as a Difference of Squares:

    3.3 Factoring: 2x8 - 3y2

    Check : 2 is not a square!

    Ruling : Binomial can not be factored as the

    difference of two perfect squares

    Trying to factor a multi variable polynomial:

    3.4 Factoring 4x16 + 6x8y2 + 9y4

    Try to factor this multi-variable trinomial using trial and error

    Factorization fails

    Final result : (2x8 - 3y2) • (4x16 + 6x8y2 + 9y4)
  2. 14 January, 02:53
    0
    The answer will be (2x8 - 3y2) • (4x16 + 6x8y2 + 9y4)
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