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18 December, 09:15

If Sin0=3/5, then cos0=?

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  1. 18 December, 09:39
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    4/5

    Step-by-step explanation:

    I believe you meant sin Ф = 3/5, since sin 0 = 0 (zero).

    sin Ф = 3/5 = (opposite side) / (hypotenuse).

    cos Ф = (adjacent side) / (hypotenuse)

    Use the Pythagorean Theorem to find the length of the adjacent side:

    (adj) ² + (opp) ² = (hyp) ² becomes (adj) ² = 5² - 3² = 25 - 9 = 16.

    Then (adj) = + √16 = + 4

    and so cos Ф = (adj) / (hyp) = 4/5
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