Ask Question
25 March, 22:00

At 10:00 a. m. two boys start out on their bikes to meet each other from towns located 68 miles apart. At 1:00 p. m. they meet. If one boy traveled 3 miles per hour faster than the other, what was the rate of speed of each boy?

+3
Answers (1)
  1. 25 March, 22:08
    0
    A = speed of one boy

    a + 3 = speed of 2nd boy

    d = speed X time ... time is 3 hrs

    68 = 3a + 3 (a + 3)

    6a = 59

    a = 59/6 = 9 5/6 miles per hour

    a + 3 = 12 5/6 miles per hou
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “At 10:00 a. m. two boys start out on their bikes to meet each other from towns located 68 miles apart. At 1:00 p. m. they meet. If one boy ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers