The length and width of each rectangle is given. Which rectangle will not have the same perimeter as the others? l = 12, w = 12 l = 14, w = 9 l = 8, w = 16 l = 13, w = 11

Rectangle 2 (l = 14, w = 9) will not have same perimeter as the others

Solution:

Given length and width of the 4 rectangles.

Rectangle 1: length = 12 units, width = 12 units

Perimeter of the rectangle = 2 (length + breadth)

Perimeter of rectangle 1 = 2 (12 + 12)

= 2 * 24

= 48 units

Perimeter of rectangle 1 = 48 units

Rectangle 2: length = 14 units, width = 9 units

Perimeter of rectangle 2 = 2 (14 + 9)

= 2 * 23

= 46 units

Perimeter of rectangle 2 = 46 units

Rectangle 3: length = 8 units, width = 16 units

Perimeter of rectangle 3 = 2 (8 + 16)

= 2 * 24

= 48 units

Perimeter of rectangle 3 = 48 units

Rectangle 4: length = 13 units, width = 11 units

Perimeter of rectangle 4 = 2 (13 + 11)

= 2 * 24

= 48 units

Perimeter of rectangle 4 = 48 units

Hence rectangle 2 (l = 14, w = 9) will not have same perimeter as the others.