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1 March, 18:59

All that is left in a packet of candy are 7 reds, 4 greens, and 2 blues, What is the probability that a random drawing yields a green followed by a red assuming that the first candy drawn is put back into the packet?

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  1. 1 March, 19:07
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    Multiply 7 (reds) by 4 (greens) to get 2/13
  2. 1 March, 19:20
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    Probability of drawing a green = 4/13

    Probability of drawing a red = 2/13

    probability of drawing a green and then a red is 4/13 * 2/13 = 6/169
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