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29 January, 18:30

Write an equation of the sine function with amplitude 9 period 3 pi

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  1. 29 January, 18:46
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    The a in front of Sin is the amplitude and the period is 2pi/k.

    To get a period of 3pi, set up an equation. 3pi = 2pi/k and solve for k.

    3pi = 2pi/k

    Multiply k on both sides.

    k * 3pi = 2pi

    Divide both sides by 3pi

    k = 2pi/3pi; k = 2/3

    y = 9Sin (2/3) x
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