A cylinder has a length of 9.00 meters and a radius of 4.32 meters. What is the cross-sectional area perpendicular to its length?

the cross-sectional area is 58.63 m²

Step-by-step explanation:

the cross-section of a cylinder perpendicular to its length is a circle whose radius is the cylinder's radius. Thus the corresponding area A is

A = π*R² = π * (4.32 m) ² = 58.63 m²

therefore the cross-sectional area is 58.63 m²

CSA = 58.63 m^2

Therefore, the cross-sectional area perpendicular to its length is 58.63 m^2

Step-by-step explanation:

The cross sectional area of a cylinder that is perpendicular (that means at angle 90°) to the length of the cylinder is the area of the circular top of the cylinder when viewing the cylinder from the top. It can be expressed mathematically as;

CSA = πr^2 ... 1

Where r is the radius of the cylinder.

Given;

radius r = 4.32 m

length l = 9.00 m

Substituting the value of r into equation 1;

CSA = π * (4.32) ^2

CSA = 58.63 m^2

Therefore, the cross-sectional area perpendicular to its length is 58.63 m^2