What is the solution set for this linear quadratic system of equations

y=*2-*-12. y-*-3=0

1. rearrange equation (step only used when necessary)

-> 2x-x-12=y, y = x+3 (I subtracted the Y from both sides and then divided everything by - 1 to get rid of the number.

2. then you can solve with the equations equaling each other

-> 2x-x-12=x+3