Ask Question
7 February, 18:12

A box of penut-buyer crackers was diverse evenly among 6 children. each child got 9 crackers how many cracker were in the box A. 54 B48 c38 or d36

+3
Answers (1)
  1. 7 February, 18:35
    0
    A. 54. Multiply 6 by 9
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A box of penut-buyer crackers was diverse evenly among 6 children. each child got 9 crackers how many cracker were in the box A. 54 B48 c38 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers