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9 February, 03:40

4x2 + 19x-5

Which two binomials are factors of the trinomial?

+5
Answers (2)
  1. 9 February, 03:43
    0
    The factors are (4x-1) (x+5).

    Step-by-step explanation:

    4x^2+19x-5

    Break the middle term:

    First multiply the coefficient of first term by the constant.

    4*5=20

    Now find any two numbers whose product = 20 and whose sum is equal to the middle term.

    20*1 = 20

    20-1 = 19

    Now break the middle term:

    4x^2+20x-x-5

    Now group the first two terms and last two terms:

    (4x^2+20x) - (x+5)

    Now take the common from each group.

    4x (x+5) - 1 (x+5)

    (4x-1) (x+5).

    Thus the factors are (4x-1) (x+5) ...
  2. 9 February, 04:04
    0
    (4x - 1) (x + 5)

    Step-by-step explanation:

    4x2 + 19x-5

    (4x) (x)

    We need to get - 5 The factors are - 1 and 5 and 1 and - 5

    4*5 = 20

    so the 5 will be on the outside We do this because we have + 19 on the inside

    (4x - 1) (x + 5)

    Lets check

    FOIL

    4x^2 + 20x - x - 5 = 4x^2 + 19x-5
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