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16 November, 06:52

Two times the sum of three consecutive odd integers is fifteen more than three times the largest of the integers. Find the integers?

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  1. 16 November, 06:57
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    Answer: 5, 7, 9

    Step-by-step explanation:

    1st#: 2k+1

    2nd#: 2k+3

    3rd#: 2k+5

    2 (2k+1 + 2k+3 + 2k+5) = 3 (2k+5) + 15

    2 (6k + 9) = 6k + 15 + 15

    12k + 18 = 6k + 30

    6k = 12

    k = 2

    1st#: 2k+1 = 2 (2) + 1 = 5

    2nd#: 2k+3 = 2 (2) + 3 = 7

    3rd#: 2k+5 = 2 (2) + 5 = 9
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