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4 February, 02:44

A number cube has the numbers 1, 2, 5, 5, 6, and 6 on its faces. Match the probability with the outcome. 1. P (5 ∪ 6) 2. P (2 ∪ 5 ∪ 6) 3. P (1 ∪ 2) 4. 0 P (4)

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  1. 4 February, 02:56
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    1. P (5 U 6) = 2/3

    2. P (2 U 5 U 6) = 5/6

    3. P (1 U 2) = 1/3

    4. P (4) = 0

    Step-by-step explanation:

    As the number cube has 6 sides,

    So,

    Total outcomes = {1,2,5,5,6,6}

    n (S) = 6

    Now,

    1. P (5U6) = P (5) + P (6)

    P (5) = 2/6=1/3

    P (6) = 2/6=1/3

    P (5U6) = 1/3 + 1/3 = 2/3

    2. P (2 U 5 U 6) = P (2) + P (5) + P (6)

    P (2) = 1/6

    P (5) = 2/6

    P (6) = 2/6

    P (2 U 5 U 6) = 1/6 + 2/6 + 2/6

    = 5/6

    3. P (1 U 2) = P (1) + P (2)

    P (1) = 1/6

    P (2) = 1/6

    P (1 U 2) = 1/6 + 1/6

    = 2/6 = 1/3

    4. P (4) = 0

    As 4 is not in the outcomes, it's probability will be zero ...
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