Five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find their present ages

Question

Jacqueline Tyler

Mathematics

30 August, 08:50

Five years ago a man was seven times as old as his son. five years hence the gather would be three times as old as his son. find their present ages

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Answers (1)

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Mya Hahn · Answer 1

Father = x

son = y

x-5 = 7 (y-5)

x + 5 = 3 (y+5) solve the system

x-5 = 7y-35

x+5 = 3y + 15

x-5 = 7y-35

-x-5 = - 3y - 15

-10 = 4y - 50

+50 + 50

40 = 4y

10 = y

Solve for X

x+5 = 3 (10) + 15

x+5 = 45

x = 40

The father is 40yrs old and the son is 10yrs old.