Ask Question
30 September, 05:57

Solve the old 2x+log12=3 round to the nearest hundredth if necessary

6,000

24,000

166.67

41.67

+4
Answers (1)
  1. 30 September, 06:22
    0
    41.67

    Step-by-step explanation:

    log 2x+log12=3

    log (a) + log (b) = log (ab)

    log (2x*12) = 3

    log (24x) = 3

    raise each side to the power of 10

    10 ^ log (24x) = 10 ^3

    24x = 1000

    divide by 24

    24x/24 = 1000/24

    x = 41.666666666 ...

    rounding to the nearest hundredth

    41.67
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Solve the old 2x+log12=3 round to the nearest hundredth if necessary 6,000 24,000 166.67 41.67 ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers