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22 May, 17:41

Find three consecutive integers that have an average of 53

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  1. 22 May, 17:44
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    Consecutive intergers are 1 away from each other so

    numbers are

    x, x+1, x+2

    average is found by adding the numbers up and dividng the total by the number of numbers you have

    so we add x+x+1+x+2 up and divide it by 3 (3 numbers)

    x+x+1+x+2=x+x+x+1+2=3x+3

    (3x+3) / 3=53

    [3 (1x+1) ]/3=53

    3/3 times 1x+1=52

    1x+1=53

    subtract 1 from both sides

    x=52

    subsitute

    x+1 is the second

    x+2 is the third

    x+1=52+1=53

    x+2=52+2=54

    numbers are 52,53,54
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