For whatvalue of a is 8x-8+3ax=5ax-2a an identity?

Identity means that equation is true no matter what.

So we just need to rearrange equation.

8x - 8 + 3ax = 5ax - 2a

(8+3a) x - 8 = (5a) x - 2a

Subtract both sides by 5ax

(8+3a-5a) x - 8 = - 2a

(8-2a) x - 8 = - 2a

Now add both sides by 8

(8-2a) x = 8-2a

Notice that coefficient of x in left side is same as constant in right side.

For equation to be true, no matter what value of x, 8-2a must be 0

Set 8-2a equal to 0

8-2a = 0

8 = 2a

a = 4

Final answer: a = 4