Bryan cut 2 peaches that were the same size for lunch. he cut one peach into fourths and the other into sixths. bryan ate 3/4 of the first peach. his brother ate 5/6 of the second peacb. who atr more peach? explain the strategy you used.

Question

Jeffery Levy

Mathematics

22 July, 17:24

Bryan cut 2 peaches that were the same size for lunch. he cut one peach into fourths and the other into sixths. bryan ate 3/4 of the first peach. his brother ate 5/6 of the second peacb. who atr more peach? explain the strategy you used.

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Answers (1)

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Sandra Murillo · Answer 1

Ok lets do the math.

First peach to fourths

Second peach to sixths

Bryan ate 3/4 of the first peach

His brother ate 5/6 of the second peach

Convert these fractions to have a equivalent denominator

3/4 = 18/24

5/6 = 20/24

So His brother in total would eat the most amount of peach.