Ask Question
16 February, 02:48

If f (x) = x^2-x and g (x) = x+1, determine f (g (x)) in simplest from

+5
Answers (2)
  1. 16 February, 02:55
    0
    f (g (x)) = x^2 + x

    Step-by-step explanation:

    To find f (g) (x), we substitute g (x) in for x in the function f (x)

    f (x) = x^2 - x

    f (g (x)) = g (x) ^2 - g (x)

    = (x+1) ^2 - (x+1)

    = (x+1) * (x+1) - (x+1)

    FOIL the square

    (x+1) (x+1)

    First x*x = x^2

    outer x*1 = x

    inner 1*x = x

    last 1*1 = 1

    Add them together

    x^2 + x+x+1 = x^2+2x+1

    f (g (x)) = (x+1) * (x+1) - (x+1)

    = x^2+2x+1 - (x+1)

    Distribute the - 1

    = x^2 + 2x+1 - x-1

    = x^2 + x
  2. 16 February, 03:17
    0
    f (g (x)) is basically replacing the x with g (x).

    So, f (x) = (g (x)) ^2 - g (x)

    g (x), in turn, equals x+1

    Replace g (x) with x+1

    (x+1) ^2 - (x+1)

    Expand: x^2+x+x+1 - x - 1

    Cancel out x and 1

    f (g (x)) = x^2+x

    If you require factoring it's

    f (g (x)) = x (x+1)
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “If f (x) = x^2-x and g (x) = x+1, determine f (g (x)) in simplest from ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers