The largest possible circle is cut out of a square whose side length is 8 feet. What will be the approximate area, in square feet, of the remaining board? (where

13.76ft²

Step-by-step explanation:

Side of square: d=8ft

Area of board: Sb=d*d=64ft²

Area of circle: Sc=pi*r²=pi * (d/2) ²=pi*d²/4=pi*64/4 = 16*pi=50.24ft²

Remainin area: Sb-Sc=64-50.24=13.76ft²

Area of remaining board is 13.728 feet²

Step-by-step explanation:

Given; Square side length = 8 feet

Therefore, the diameter of the cut out circle = 8 feet, then Radius = 4 feet

The approximate area, in square feet, of the remaining board will be the are of the square minus the ares of the cut out circle.

Area of the square = S²

= (8 feet) ²

= 64 feet²

Area of the cut circle = π (4 feet) ²

= 3.142 x 16 feet²

= 50.272 feet²

Area of remaining board = Area of the square - Area of the cut circle

Area of remaining board = 64 feet² - 50.272 feet²

Area of remaining board = 13.728 feet²