Solve the following system of equations using the

substitution method:

y = x2 + 3x - 12

y = x + 3

y = x² + 3x - 12

y = x + 3

Substitute the second value of y into the first equation, and you'll have

x + 3 = x² + 3x - 12

Now solve

0 = x² + 2x - 15

0 = (x + 5) (x - 3)

x = - 5, x = 3

With - 5, you'll get y = - 2

With 3, you'll get y = 6

The solutions are 3 and - 5

Step-by-step explanation:

x+3=x^2+3x-12

x^2+2x-15

= (x-3) (x+5)