A toy company is releasing a new catapult for water balloons that launches them at 9.8 meters per second from a stand 0.6 meters tall. The function f (x) = - 4.9x2 + 9.8x + 0.6 describes the path of the water balloon, where x is the amount of time since the launch. While the mathematical range is y ≤ 5.5, how does the reasonable range compare? The reasonable range is limited to y ≥ 0. The reasonable range is limited to y ≥ 0.6. The reasonable range is limited to 0 ≤ y ≤ 5.5. The reasonable range is limited to 0.6 ≤ y ≤ 5.5.

Question

Adrian Weber

Mathematics

11 March, 06:56

A toy company is releasing a new catapult for water balloons that launches them at 9.8 meters per second from a stand 0.6 meters tall. The function f (x) = - 4.9x2 + 9.8x + 0.6 describes the path of the water balloon, where x is the amount of time since the launch. While the mathematical range is y ≤ 5.5, how does the reasonable range compare? The reasonable range is limited to y ≥ 0. The reasonable range is limited to y ≥ 0.6. The reasonable range is limited to 0 ≤ y ≤ 5.5. The reasonable range is limited to 0.6 ≤ y ≤ 5.5.

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Answers (2)

Know the Answer?

Pranav Chen · Answer 1

Step-by-step explanation: so whats the question

Marin Melendez · Answer 2

The reasonable range is limited to 0.6 ≤ y ≤ 5.5.

Step-by-step explanation:

The function f (x) = - 4.9x^2 + 9.8x + 0.6 describes the path of the water balloon, where x is the amount of time since the launch. While the mathematical range is y ≤ 5.5

x is the amount of time, time cannot be negative

we find out the height f (x) when x=0 so that we find the reasonable range

When x=0, f (0) = - 4.9 (0) ^2 + 9.8 (0) + 0.6 = 0.6

the range start at 0.6 and it is less than 5.5

The reasonable range is limited to 0.6 ≤ y ≤ 5.5.