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11 November, 12:42

What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = - 1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = 1

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = 1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = - 1

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Answers (1)
  1. 11 November, 13:07
    0
    The unique answer is A

    sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = - 1

    (just put the Θ in the trigonometry circle)
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