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21 April, 02:32

Which expression is equivalent to (2mn) ^4/6m^-3 n^-2? Assume m=0 n=0

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  1. 21 April, 02:41
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    7m - (7n-18m)

    Step-by-step explanation:

    m=0, n=0.

    8m^7n^6/3 10m^7n^6/3 8m^16n^12/3 m^4n^6/3

    -7m - (3n - (8m-4n-10m)

    -7m - (3n - (8m-4n+10m))

    -7m - (3n - (18m-4n))

    -7m - (3n-18m+4n)

    -7m - (7n-18m)
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