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Find 3 consecutive integers such that 3 times the sum of the first and third is 84 less than 12 times the secind

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  1. 4 May, 07:36
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    Let x = 1st integer

    x + 1 = 2nd integer

    x + 2 = 3rd integer

    3 (x + x + 2) = 12 (x + 1) - 84

    3 (2x + 2) = 12x + 12 - 84

    6x + 6 = 12x - 72

    -6x = - 78

    x = 13

    Answer: 13, 14, 15
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