29 January, 09:06
Find the solution (s) for x in the equation below. x^2 - 9x + 20 = 0
29 January, 10:08
x = 4, x = 5
x² - 9x + 20 = 0
Consider the factors of the constant term ( + 20) which sum to give the coefficient of the x - term ( - 9)
The factors are - 4 and - 5, since
- 4 * - 5 = + 20 and - 4 - 5 = - 9, thus
(x - 4) (x - 5) = 0
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x - 5 = 0 ⇒ x = 5
29 January, 11:05
Solve the equation x^2-9x+20=0. First, we need to factorise the equation on the left hand side, this can be done by finding two numbers that add together to make the 'b' coefficient (-9) and multiply to make the 'c' coefficient (20). This will give - 5 and - 4. Therefore, (x-5) (x-4) = 0.
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