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2 January, 01:02

What are the side lengths in a rectangle if the area is 60 and perimeter is 32?

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Answers (2)
  1. 2 January, 01:22
    0
    A = L*W

    P = 2 (L+W)

    60 = LW

    32=2 (L+W); 16 = L+W; W=16-L

    Plug that into the area equation:

    60=L * (16-L); L^2-16L+60=0; Factoring: (L-10) (L-6) = 0,

    so L can be 10, or 6.

    If L is 6, W is 10, and If L is 10, W is 6.

    Thus the side lengths are 10, and 6.
  2. 2 January, 01:26
    0
    It can be 10 times 6 or 8 (7.5) both = 60 A=bh A=10 (6) = 60 or A=8 (7.5) = 60
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