What are the side lengths in a rectangle if the area is 60 and perimeter is 32?

A = L*W

P = 2 (L+W)

60 = LW

32=2 (L+W); 16 = L+W; W=16-L

Plug that into the area equation:

60=L * (16-L); L^2-16L+60=0; Factoring: (L-10) (L-6) = 0,

so L can be 10, or 6.

If L is 6, W is 10, and If L is 10, W is 6.

Thus the side lengths are 10, and 6.

It can be 10 times 6 or 8 (7.5) both = 60 A=bh A=10 (6) = 60 or A=8 (7.5) = 60