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31 October, 08:12

Find three consecutive even integers such that the sum of the smallest to the largest 36

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Answers (2)
  1. 31 October, 08:17
    0
    First, I would set up an equation (assuming 36 is the sum of all 3 numbers).

    x + (x+2) + (x+4) = 36

    3x+6=36

    -6 - 6

    3x=30

    - - - - - -

    3 3

    x=10

    Now, we just plug in the numbers to find the consecutive integers

    10 + (10+2) + (10+4)

    10+12+14

    So your 3 consecutive even integers are 10,12 and 14
  2. 31 October, 08:38
    0
    If they were all the same integer, then each one would be

    1/3 of 36, and you would have

    12 + 12 + 12 = 36.

    But you don't want them to all be the same number. You

    want them to be three consecutive even numbers.

    Fine! Take 2 away from the first 12, and glue it onto the last 12.

    Their sum doesn't change, but now you have

    10 + 12 + 14 = 36.
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