A bag contains 7 red marbles, 8 blue marbles and 5 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that both marbles drawn will be green?

Answer: 0.053

Step-by-step explanation:

n (r) = 7

n (b) = 8

n (g) = 5

Total number of marbles = 20

The probability that both marbles drawn will be green will be

The probability of the first being green = 5/20 and the probability that the second marble is green = 4/19.

We will multiply the two together, we have

5/20 x 4/19 = 20/380 = 0.05263157895

Therefore : the probability, to the nearest 10th of a percent, that both marbles drawn will be green will be 0.053