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14 July, 09:09

A car is moving with an initial velocity of 10 mph accelerates at the rate of a (t) = 2.5t mph per second for 5 seconds. How fast is the car going when the 5 seconds are up?

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Answers (2)
  1. 14 July, 09:17
    0
    The car is going up at a speed of 22.5 mph

    Step-by-step explanation:

    In this question, we are asked to calculate the speed of a moving car which started moving at an initial velocity for a specific period of time.

    To calculate this, we use one of the basic equations of motion;

    v = u + at

    Where v is the final velocity, u is the initial velocity and t is the time

    From the question, we can identify the parameters as follows;

    v = ?

    u = 10mph

    a = 2.5t mph per second for 5 seconds.

    Hence a here would be 2.5 * 5 = 12.5

    Now, let's put these values in the equation

    v = 10 + 12.5

    v = 22.5 mph
  2. 14 July, 09:21
    0
    22.5 mph

    Step-by-step explanation:

    According to the question, a car is moving with an initial velocity of 10 mph accelerates at the rate of a (t) = 2.5t mph per second for 5 seconds and we are asked to find out how fast is the car going when the 5 seconds are up?

    The formula to be applied here so as to derive our answer is

    v = u + at

    Where v is the final velocity, u is the initial velocity, acceleration and t is the time

    V = ?

    U = 10

    A = 2.5t ≈ 2.5 * 5 = 12.

    T = 5

    10 + 12.5 = 22.5 mph
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