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29 March, 06:21

A ball, dropped vertically, falls d metres in t seconds. D is directly proportional to the square of t. The ball drops 80 metres in the first 4 seconds. How far does the ball drop in the next 8 seconds?

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  1. 29 March, 06:45
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    640 m.

    Step-by-step explanation:

    D = kt^2 where d is the constant of proportionality.

    D = 80 m when t = 4 seconds so:

    80 = k*4^2

    k = 80 / 16 = 5.

    So the equation of motion is D = 5t^2.

    When t = 8+4 = 12 seconds D = 5*12^2 = 5*144

    = 720 m

    So the distance the ball drops in the next 8 seconds = 720 - 80

    = 640 m.
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