If a circle in Quadrant IV of the coordinate plane is tangent to the x - and y-axes and has a radius of 2, what is its equation?

A. - 2) 2 + (-2) 2=4

B. (-2) 2 + (+2) 2=4

C. (+2) 2 + (-2) 2=4

D. (-2) 2 + (+2) 2=2

B. (x - 2) ^2 + (y + 2) ^2 = 4.

Step-by-step explanation:

The general form of the equation is

(x - a) ^2 + (y - b) ^2 = r^2 where (a, b) is the center and r is the radius of the circle.

The radius is 2 so r^2 = 4.

The center of the circle is at (2, - 2) so the equation is:

(x - 2) ^2 + (y + 2) ^2 = 4.

b is your answer