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1 January, 23:08

Given the equations x = 6y, 4y = 9z, and (3x) (9z) = ky, what is the value of k in terms of y, if y ≠ 0?

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  1. 1 January, 23:36
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    X=6y

    x/6=y

    4y=9z

    (4/9) y=z

    4 (x/6) = 9z

    (2/3) x=9z

    x (2/3) / 9=z

    (2/27) x=z

    (3x) (9z) = ky

    (3 (6y)) (9 ((4/9) y)) = k (y)

    (18y) (4y) = k (y)

    (72y^2) = k (y)

    y (72y) = y (k)

    72y=k
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