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21 November, 10:00

Which identity could be used to rewrite the expression x^6-27

A difference of squares

B two squares

C difference of cubes

D quadratic formula

+3
Answers (2)
  1. 21 November, 10:05
    0
    C. Difference of cubes

    This is because the expression:

    x⁶ - 27

    can be simplified to:

    (x²) ³ - 3³
  2. 21 November, 10:23
    0
    The answer is C: difference of cubes

    proof

    x^6-27 = (x^2) ^3 - 3^3, because (x^2) ^3 = x^2*3=x^6
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