What is the solution to the system of equations?

y = 1/3 x - 10

2x + y = 4

(-8, 6)

(-6, 16)

(6, - 8)

(16, - 6)

Y = 1/3x - 10

sub in 1/3x - 10 in for y in the other equation

2x + y = 4

2x + 1/3x - 10 = 4 ... multiply everything by 3 to get rid of factions

6x + x - 30 = 12

7x = 12 + 30

7x = 42

x = 42/7

x = 6

2x + y = 4

2 (6) + y = 4

12 + y = 4

y = 4 - 12

y = - 8

solution is : (6,-8)