You are planning to put a new digital flat t. v on a wall that is 12ft long and 9ft high. the digital t. v has a diagonal of 72 inches. the length of the t. v. is twice the width of the tv how much of the wall will still need to be decorated around the tv?

Question

Sam Golden

Mathematics

1 April, 01:13

You are planning to put a new digital flat t. v on a wall that is 12ft long and 9ft high. the digital t. v has a diagonal of 72 inches. the length of the t. v. is twice the width of the tv how much of the wall will still need to be decorated around the tv?

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Answers (1)

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Camryn Holland · Answer 1

Area of wall = 9 * 12 = 108 ft^2

Width of TV = x

Lenght = 2x

Diagonal of TV = 72 " = 6 ft

x^2 + (2x) ^2=6^2

x^2+4x^2=36

5x^2=35

x^2=36/5

x=sqrt (36/5)

Width = 2.68 ft.

Length = 2.68 * 5.36 = 14.36 ft^2

Area of wall - area of tv = 108 - 14.36 = 93.64 ft