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Which shows the equation below written in the form ax2 + bx + c = 0?

x + 10 = 3 (x - 1) ^2

A. 3x2 - 5x + 13 = 0

B. 3x2 - 7x + 13 = 0

c. 3x2-77-7 = 0

D. 3x2 - 5x - 7 = 0

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Answers (2)
  1. 2 June, 15:18
    0
    3x² - 7x - 7 = 0

    Step-by-step explanation:

    Given

    x + 10 = 3 (x - 1) ² ← expand the factor

    x + 10 = 3 (x² - 2x + 1) ← distribute by 3

    x + 10 = 3x² - 6x + 3 (subtract x + 10 from both sides)

    0 = 3x² - 7x - 7 or

    3x² - 7x - 7 = 0
  2. 2 June, 15:31
    0
    C

    Step-by-step explanation:

    x+10=3 (x2-2x+1)

    x+10=3x2-6x+3

    3x2-7x-7=0
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