There are 6 sets of coins on the table. There is only one coin in the first set, 2 coins in the second set, 3 coins in the third set, 4 coins in the fourth set, 5 coins in the fifth set, and 6 coins in the sixth set. In each step, it is possible to add a coin to any two sets. Is it possible that after some steps the number of coins in each of the sets will be equal

if you answer correctly in first 10 minutes ill give brainliest

Question

Alonso Higgins

Mathematics

22 May, 21:16

There are 6 sets of coins on the table. There is only one coin in the first set, 2 coins in the second set, 3 coins in the third set, 4 coins in the fourth set, 5 coins in the fifth set, and 6 coins in the sixth set. In each step, it is possible to add a coin to any two sets. Is it possible that after some steps the number of coins in each of the sets will be equal

if you answer correctly in first 10 minutes ill give brainliest

+1

Answers (1)

Know the Answer?

Braniac · Answer 1

no

Step-by-step explanation:

The total number of coins in all sets is 21, an odd number. In order for there to be equal numbers in all sets, the total number of coins must be even. Each step adds an even number of coins, so there is no number of steps that will add an odd number of coins to make the total be even.