Fred takes $20 to the arcade and it costs $2 for every game he plays. Fred needs to leave the arcade with $5.00 to pay for lunch, what is the most number of games he can play?

Question

Kaylee Schwartz

Mathematics

11 July, 10:51

Fred takes $20 to the arcade and it costs $2 for every game he plays. Fred needs to leave the arcade with $5.00 to pay for lunch, what is the most number of games he can play?

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Answers (2)

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Lukas Walker · Answer 1

So, Fred has $20 to start. If he needs to set aside $5 for lunch, he has $15 to spend on games.

If games are $2 per play, $15 divided by $2 is $7.50, which means he can only play 7 games, and have $0.50 left over.

Jerome Rowe · Answer 2

Fred can play 7 games and he will have 6 dollars left over