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13 August, 15:38

Use a method of completing the square in order to rewrite the function f (x) = x^2+5x-2 in vertex form, f (x) = a (x-h) ^2+k where (h, k) is the vertex of the parabola.

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  1. 13 August, 15:41
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    f (x) = x² + 5x - 2

    f (x) + 2 = x² + 5x - 2 + 2

    f (x) + 2 = x² + 5x

    f (x) + 2 = x (x) + x (5)

    f (x) + 2 = x (x + 5)

    f (x) = x (x + 5) - 2

    (h, k) = (-5, 2)
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