Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 192 miles in the same time that Dana travels 183 miles. If Chuck's rate of travel is 3 mph more than Dana's, and they travel the same length of time, at what speed does Chuck travel?

Step-by-step explanation:

speed=distance/time

64miles/hr

Step-by-step explanation:

Chuck's details:

distance = 192miles

Dana's details:

distance = 183miles

So. Let the speed of Dana be Xmiles/hr then speed of Chuck's will be (X + 3) miles/hr

Since they both traval at the since time t then

Speed = distance/time

For Chuck's: (X + 3) = 192/t

Making t as subject of formula

t = 192 / (X + 3)

For Dana: X = 183/t

Making t as subject of formula

t = 183/X

So. since t is constant for both Chuck's and Dana then:

192 / (X + 3) = 183/X

Cross multiple

192X = 183 (X + 3)

192X = 183X + 549

Collect like terms

192X - 183X = 549

9X = 549

Divide through by 9

X = 549/9

X = >61 miles/hr

Speed for Chuck's is X + 3

= 61 + 3

= 64miles/hr