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16 May, 04:51

Find the average value of the function on the given interval.

f (x) = x^2-4; [0,5]

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  1. 16 May, 05:12
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    Average=29/6=4.83

    Step-by-step explanation:

    F (0) = 0^2-4=-4

    F (1) = 1^2-4=-3

    F (2) = 2^2-4=0

    F (3) = 3^2-4=5

    F (4) = 4^2-4=10

    F (5) = 5^2-4=21

    The average is = total/6

    Average=29/6=4.83
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