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29 August, 03:02

Patty made a banner that has an area of 36 square inches,. The length and width of the banner are whole numbers. The length is 4 times greater than the width. What are the dimensions of the banner?

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Answers (2)
  1. 29 August, 03:16
    0
    The length of the banner is 12 inches while the width of the banner is 3 inches

    Step-by-step explanation:

    Here we have the area of the rectangular banner = 36 in²

    Formula for the area of the banner is Length, L * Width, W

    We are told the length is 4 times greater than the width.

    That is, L = 4·W

    Therefore, the area of the banner = L * W = 4·W * W = 4·W² = 36 in²

    ∴ W = √ (36/4) = 3 inches

    L = 4·W = 4 * 3 inches = 12 inches

    Therefore, the dimensions of the banner are

    Length of banner = 12 inches

    Width of banner = 3 inches.
  2. 29 August, 03:30
    0
    Answer: width = 3 inches; length = 12 inches.

    Step-by-step explanation:

    From the question, the length is 4 times greater than the width.

    Let the width of the banner be represented by y.

    Since the length is 4 times greater than the width. It will be denoted as:

    Length = 4 * y = 4y

    Since area = length*width

    4y * y = 36

    4y^2 = 36

    Divide both side by 4

    y^2 = 36/4

    y^2 = 9

    We have to find the square root of 9

    y = √9

    y = 3

    The width is 3 inches.

    The length will be: (3*4) = 12 units.
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