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Simon Estrada
Mathematics
27 December, 10:40
If the value of sinx=0.42, what is cos x?
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Andrea Ruiz
27 December, 10:54
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From the relation of
sin (x) ^2 + cos (x) ^2 = 1
(0.42) ^2 + cos (x) ^2 = 1
cos (x) ^2 = 1 - (0.42) ^2
cos (x) = √ (1 - (0.42) ^2)
cos (x) = 0.9075
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