Sweet corn of a certain variety is known to produce individual ears of corn with a mean weight of 8 ounces. A

farmer is testing a new fertilizer designed to produce larger ears of corn, as measure by their weight. He finds

that 28 randomly-selected ears of corn grown with this fertilizer have a mean weight of 8.25 ounces and a

standard deviation of 0.8 ounces. There are no outliers in the data. Do these samples provide convincing

evidence at the. 05 level that the fertilizer had a positive impact on the weight of the corn ears?

Question

Kennedi Potts

Mathematics

21 February, 06:53

Sweet corn of a certain variety is known to produce individual ears of corn with a mean weight of 8 ounces. A

farmer is testing a new fertilizer designed to produce larger ears of corn, as measure by their weight. He finds

that 28 randomly-selected ears of corn grown with this fertilizer have a mean weight of 8.25 ounces and a

standard deviation of 0.8 ounces. There are no outliers in the data. Do these samples provide convincing

evidence at the. 05 level that the fertilizer had a positive impact on the weight of the corn ears?

+5

Answers (1)

Know the Answer?

Jaiden Turner · Answer 1

H0: μ = 8

H1: μ > 8

t = (8.25 - 8) / (0.8/sqrt (28)) = 1.654

t_table = 1.703

since t_calc < t_table, we accept H0, and conclude that the sample does not provide cnvincing evidence that the fertilizer had a positive impact on the weight of the corn ears at 0.05 level of significant.