Ask Question
1 February, 10:58

There is a reservoir with five channels bringing in water. If only the first channel is open, the reservoir can be filled in13 of a day. The second channel by itself will fill the reservoir in 1 day, the third channel in212 days, the fourth one in 3 days, and the fifth one in 5 days. If all the channels are open together, how long will it take to fill the reservoir?

+4
Answers (1)
  1. 1 February, 11:21
    0
    approximately 0.2 days

    Step-by-step explanation:

    Flow is defined as:

    Q = V/t

    where Q is flow, V is volume, and t is time

    Let's call Vr to the volume of the reservoir, then for the first channel:

    Q1 = Vr/t1

    Replacing with t1 = 1/3 of day:

    Q1 = Vr / (1/3) = 3*Vr

    Similarly, or the other channels:

    Q2 = Vr/1 = Vr

    Q3 = Vr / (2 1/2) = 2/5*Vr

    Q4 = Vr/3

    Q5 = Vr/5

    When all channels are open, the time needed to fill the reservoir is:

    Vr = t * (Q1 + Q2 + Q3 + Q4 + Q5)

    Replacing with the previous equivalences:

    Vr = t * (3*Vr + Vr + 2/5*Vr + Vr/3 + Vr/5)

    Vr = t*4.93*Vr

    1/4.93 = t

    0.2 = t
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “There is a reservoir with five channels bringing in water. If only the first channel is open, the reservoir can be filled in13 of a day. ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers