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14 October, 00:28

Use the Racetrack Principle and the fact that sin 0 = 0

to show that sin x (less than or equal to) x for all x (greater than or equal to) 0.

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  1. 14 October, 00:45
    0
    Oh maybe that since the derivative of sine is cosine and cosine is bounded above by 1, then sin⁡ (x) - sin⁡ (0) / x-0 ≤1

    /frac{/sin (x) - / sin (0) }{x-0}/leq 1 so sin⁡ (x) ≤ x
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