Solve:

sin (2x) = sqrt (3) / 2

I

In order to solve this you will need to use inverse sin function like this:

sin^-1 ((-sqrt3) / 2) = 2x

sin^-1 ((-sqrt3/2) = 5pi/3

5pi/3 = 2x

(5pi/3) / 2

5pi/6

is the answer.

I hope this goes good