If sin A = 0.29, cos A = 0.96, sin B = 0.42, and cos B = 0.91, what is sin (A+B) ?

a) 0.67

b) 1.00

c) - 0.14

d) 0.71

Question

Jamari Hendrix

Mathematics

26 January, 10:10

If sin A = 0.29, cos A = 0.96, sin B = 0.42, and cos B = 0.91, what is sin (A+B) ?

a) 0.67

b) 1.00

c) - 0.14

d) 0.71

+5

Answers (1)

Know the Answer?

Elise · Answer 1

The answer is A.

Step-by-step explanation:

Using the formula, sin (A+B) = sinAcosB + cosA sinB:

sin (A+B) = (0.29*0.91) + (0.96*0.42)

= 0.2639 + 0.4032

= 0.67 (2. dp)

If sin A = 0.29, cos A = 0.96, sin B = 0.42, and cos B = 0.91, what is sin (A+B) ?a) 0.67b) 1.00c) - 0.14d) 0.71

If sin A = 0.29, cos A = 0.96, sin B = 0.42, and cos B = 0.91, what is sin (A+B) ?

a) 0.67

b) 1.00

c) - 0.14

d) 0.71